Home ≫ Arithmetic Aptitute ≫ Average ≫ Page 6
51. Find the average of these 9 consecutive numbers. 5,6,7,8,9,10,11,12,13
  A.  11
  B.  9
  C.  7
  D.  13
     
   
View Answer

Shortcut:
The average of n (where n is an odd number) consecutive numbers (even/odd/natural numbers) is always the middle number.
Case 1. Let consecutive natural numbers are 1,2,3,4 and 5
Here n = 5
∴ Average =
1+2+3+4+5 / 5
= 3
Hence, 3 lies in the middle.

Case 2. Let consecutive odd numbers are 1,3,5,7 and 9
Here n = 5
∴ Average =
1+3+5+7+9 / 5
=
25 / 5
= 5
Hence, 5 lies in the middle.

Case 3. Let consecutive even numbers are 2,4,6,8 and 10
Here n = 5
∴ Average =
2+4+6+8+10 / 5
=
30 / 5
= 6
Hence, 6 lies in the middle.

Using these shortcut method, we can conclude that average of 9 consecutive numbers 5,6,7,8,9,10,11,12 and 13 is 9 because it lies in the middle.

52. Find the average of the consecutive numbers given: 25,26,27,28,29,30,31
  A.  30
  B.  26
  C.  28
  D.  24
     
   
View Answer

Shortcut:
The average of n (where n is an odd number) consecutive numbers (even/odd/natural numbers) is always the middle number.
Case 1. Let consecutive natural numbers are 1,2,3,4 and 5
Here n = 5
∴ Average =
1+2+3+4+5 / 5
= 3
Hence, 3 lies in the middle.

Case 2. Let consecutive odd numbers are 1,3,5,7 and 9
Here n = 5
∴ Average =
1+3+5+7+9 / 5
=
25 / 5
= 5
Hence, 5 lies in the middle.

Case 3. Let consecutive even numbers are 2,4,6,8 and 10
Here n = 5
∴ Average =
2+4+6+8+10 / 5
=
30 / 5
= 6
Hence, 6 lies in the middle.

Using these shortcut method, we can conclude that average of 7 consecutive numbers 25,26,27,28,29,30 and 31 is 28 because it lies in the middle.

53. Find the average of the consecutive odd numbers: 33,35,37,39,41,43,45
  A.  43
  B.  41
  C.  36
  D.  39
     
   
View Answer

Shortcut:
The average of n (where n is an odd number) consecutive numbers (even/odd/natural numbers) is always the middle number.
Case 1. Let consecutive natural numbers are 1,2,3,4 and 5
Here n = 5
∴ Average =
1+2+3+4+5 / 5
= 3
Hence, 3 lies in the middle.

Case 2. Let consecutive odd numbers are 1,3,5,7 and 9
Here n = 5
∴ Average =
1+3+5+7+9 / 5
=
25 / 5
= 5
Hence, 5 lies in the middle.

Case 3. Let consecutive even numbers are 2,4,6,8 and 10
Here n = 5
∴ Average =
2+4+6+8+10 / 5
=
30 / 5
= 6
Hence, 6 lies in the middle.

Using these shortcut method, we can conclude that average of 7 consecutive odd numbers 33,35,37,39,41,43 and 45 is 39 because it lies in the middle.

54. Find the average of the consecutive odd numbers given as: 71,73,75,77,79,81,83,85,87,89,91
  A.  81
  B.  77
  C.  83
  D.  79
     
   
View Answer

Shortcut:
The average of n (where n is an odd number) consecutive numbers (even/odd/natural numbers) is always the middle number.
Case 1. Let consecutive natural numbers are 1,2,3,4 and 5
Here n = 5
∴ Average =
1+2+3+4+5 / 5
= 3
Hence, 3 lies in the middle.

Case 2. Let consecutive odd numbers are 1,3,5,7 and 9
Here n = 5
∴ Average =
1+3+5+7+9 / 5
=
25 / 5
= 5
Hence, 5 lies in the middle.

Case 3. Let consecutive even numbers are 2,4,6,8 and 10
Here n = 5
∴ Average =
2+4+6+8+10 / 5
=
30 / 5
= 6
Hence, 6 lies in the middle.

Using these shortcut method, we can conclude that average of 11 consecutive odd numbers 71,73,75,77,79,81,83,85,87,89 and 91 is 81 because it lies in the middle.

55. Find the average of the consecutive even numbers given as: 50,52,54,56,58,60,62,64,66,68,70,72,74
  A.  66
  B.  58
  C.  62
  D.  64
     
   
View Answer

Shortcut:
The average of n (where n is an odd number) consecutive numbers (even/odd/natural numbers) is always the middle number.
Case 1. Let consecutive natural numbers are 1,2,3,4 and 5
Here n = 5
∴ Average =
1+2+3+4+5 / 5
= 3
Hence, 3 lies in the middle.

Case 2. Let consecutive odd numbers are 1,3,5,7 and 9
Here n = 5
∴ Average =
1+3+5+7+9 / 5
=
25 / 5
= 5
Hence, 5 lies in the middle.

Case 3. Let consecutive even numbers are 2,4,6,8 and 10
Here n = 5
∴ Average =
2+4+6+8+10 / 5
=
30 / 5
= 6
Hence, 6 lies in the middle.

Using these shortcut method, we can conclude that average of 13 consecutive even numbers 50,52,54,56,58,60,62,64,66,68,70,72 and 74 is 62 because it lies in the middle.

56. Find the average value of the given consecutive numbers.: 6,6,7,8,9,10,11,12,13,14
  A.  11
  B.  9.5
  C.  8.5
  D.  10
     
   
View Answer

Shortcut:
The average of n (where n is an even number) consecutive numbers (even/odd/natural numbers) is always the averae of the middle two number.
Case 1. Let consecutive natural numbers are 1,2,3,4,5 and 6
Here n = 6, middle two numbers are 3 & 4
∴ Average =
3+4 / 2
= 3.5

Case 2. Let consecutive odd numbers are 1,3,5,7,9 and 11
Here n = 6, middle two numbers are 5 & 7
∴ Average =
5+7 / 2
=
12 / 2
= 6

Case 3. Let consecutive even numbers are 2,4,6,8,10 and 12
Here n = 6, middle two numbers are 6 & 8
∴ Average =
6+8 / 2
=
14 / 2
= 7

Using these shortcut method, we can conclude that average of 10 consecutive numbers 6,6,7,8,9,10,11,12,13 and 14 is
9+10 / 2
=
19 / 2
= 9.5

Hence, average is 9.5

57. Find the average value of the given consecutive numbers.: 22,23,24,25,26,27,28,29,30,31,32,33
  A.  30
  B.  28.5
  C.  24
  D.  27.5
     
   
View Answer

Shortcut:
The average of n (where n is an even number) consecutive numbers (even/odd/natural numbers) is always the averae of the middle two number.
Case 1. Let consecutive natural numbers are 1,2,3,4,5 and 6
Here n = 6, middle two numbers are 3 & 4
∴ Average =
3+4 / 2
= 3.5

Case 2. Let consecutive odd numbers are 1,3,5,7,9 and 11
Here n = 6, middle two numbers are 5 & 7
∴ Average =
5+7 / 2
=
12 / 2
= 6

Case 3. Let consecutive even numbers are 2,4,6,8,10 and 12
Here n = 6, middle two numbers are 6 & 8
∴ Average =
6+8 / 2
=
14 / 2
= 7

Using these shortcut method, we can conclude that average of 12 consecutive numbers 22,23,24,25,26,27,28,29,30,31,32 and 33 is
27+28 / 2
=
55 / 2
= 27.5

Hence, average is 27.5

58. Find the average value of the given consecutive numbers.: 71,72,73,74,75,76
  A.  75
  B.  76.5
  C.  73.5
  D.  71.5
     
   
View Answer

Shortcut:
The average of n (where n is an even number) consecutive numbers (even/odd/natural numbers) is always the averae of the middle two number.
Case 1. Let consecutive natural numbers are 1,2,3,4,5 and 6
Here n = 6, middle two numbers are 3 & 4
∴ Average =
3+4 / 2
= 3.5

Case 2. Let consecutive odd numbers are 1,3,5,7,9 and 11
Here n = 6, middle two numbers are 5 & 7
∴ Average =
5+7 / 2
=
12 / 2
= 6

Case 3. Let consecutive even numbers are 2,4,6,8,10 and 12
Here n = 6, middle two numbers are 6 & 8
∴ Average =
6+8 / 2
=
14 / 2
= 7

Using these shortcut method, we can conclude that average of 6 consecutive numbers 71,72,73,74,75 and 76 is
73+74 / 2
=
147 / 2
= 73.5

Hence, average is 73.5

59. Find the average value of the given consecutive odd numbers.: 9,11,13,15,17,19
  A.  14
  B.  9
  C.  11
  D.  15
     
   
View Answer

Shortcut:
The average of n (where n is an even number) consecutive numbers (even/odd/natural numbers) is always the averae of the middle two number.
Case 1. Let consecutive natural numbers are 1,2,3,4,5 and 6
Here n = 6, middle two numbers are 3 & 4
∴ Average =
3+4 / 2
= 3.5

Case 2. Let consecutive odd numbers are 1,3,5,7,9 and 11
Here n = 6, middle two numbers are 5 & 7
∴ Average =
5+7 / 2
=
12 / 2
= 6

Case 3. Let consecutive even numbers are 2,4,6,8,10 and 12
Here n = 6, middle two numbers are 6 & 8
∴ Average =
6+8 / 2
=
14 / 2
= 7

Using these shortcut method, we can conclude that average of 6 consecutive odd numbers 9,11,13,15,17 and 19 is
13+15 / 2
=
28 / 2
= 14

Hence, average is 14

60. Find the average value of the given consective odd numbers: 35,37,39,41,43,45,47,49
  A.  43
  B.  42
  C.  45
  D.  39
     
   
View Answer

Shortcut:
The average of n (where n is an even number) consecutive numbers (even/odd/natural numbers) is always the averae of the middle two number.
Case 1. Let consecutive natural numbers are 1,2,3,4,5 and 6
Here n = 6, middle two numbers are 3 & 4
∴ Average =
3+4 / 2
= 3.5

Case 2. Let consecutive odd numbers are 1,3,5,7,9 and 11
Here n = 6, middle two numbers are 5 & 7
∴ Average =
5+7 / 2
=
12 / 2
= 6

Case 3. Let consecutive even numbers are 2,4,6,8,10 and 12
Here n = 6, middle two numbers are 6 & 8
∴ Average =
6+8 / 2
=
14 / 2
= 7

Using these shortcut method, we can conclude that average of 8 consecutive odd numbers 35,37,39,41,43,45,47 and 49 is
41+43 / 2
=
84 / 2
= 42

Hence, average is 42

Copyright © 2020-2022. All rights reserved. Designed, Developed and content provided by Anjula Graphics & Web Desigining .