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Rules of Simplification:
VBODMAS
V means Vinculum
B means Brackets
O means Of
D means Division
M means Multiplication
A means Addition
S means Substraction
First of all Vinculum will be solved, then Brackets, then Of, then Division, then Multiplication, then Addition and finally Substraction will be done in all questions.

1. 1 ÷
3 / 7
of (6 + 8 ×
/ 3 − 2
) +
[
1 / 5
÷
7 / 25
−
{
3 / 7
+
8 / 14
}
]
  A.  −
2 / 45
  B.  +
3 / 40
  C.  −
5 / 42
  D.  +
5 / 42
     
   
View Answer 
  1÷3/7 of (6+8×1)+[1/5÷7/25-14/14]
  = 1÷3/7 of (6+8)+[1/5×2/75-1]
  = 1÷14 +[5/7-1]
  = 1÷ 6+[-2/7]
  = 1/6-2/7
  = -5/42
2. 10
1 / 2
−
[
8
1 / 2
+
{
6 − (7−
/ 6 − 4
)
}
]
  A.  + 1
  B.  +
3 / 2
  C.  −
1 / 2
  D.  − 1
     
   
View Answer 
  = 21/2-[17/2+{6-(7-2)}]
  = 21/2-[17/2+{6-5}]
  = 21/2-[17/2+1]
  = 21/2-19/2
  = 2/2
  = 1
3. 5
1 / 4
÷
3 / 7
of
(
45 / 24
− 
/
2 / 3
+ 
5 / 6
of  
2 / 5
)
  A.  18
  B.  12
  C.  -15
  D.  14
     
   
View Answer 
 
  = 21/4÷3/7 of (15/8-1)
  = 21/4÷3/7 of7/8
  = 21/4÷3/8 
  = 21/4 ×8/3
  = 14
4. 2
2 / 3
{
(
/
7 / 8
+ 
3 / 4
×
4 / 6
)
÷ 3
1 / 4
+
7 / 8
}
  A.  +
29 / 8
  B.  +
29 / 9
  C.  +
30 / 9
  D.  −
29 / 9
     
   
View Answer 
 
  = 8/3{13/8×4/6)÷13/4+7/8}
  = 8/3{13/12×4/13+7/8}
  = 8/3{1/3+7/8}
  = 8/3{29/24}
  = 8/3 × 29/24
  = 1/3 ×29/3
  = 29/9
5. Find the value of P,  
4.5
−
[
4.5 +
{
4.5 −
(
9 −
/ 4.5 + P
)
}
]
= 0
  A.  + 2
  B.  − 1
  C.   0
  D.  + 1
     
   
View Answer 
  4.5-[4.5+{4.5-(4.5+P)}]=0
  4.5-[4.5+{4.5-4.5-P}]=0
  4.5-[4.5-P]=0
  4.5-4.5+P=0
  P=0
6. If M = 4, N = 3, then find the value of,
M
÷
(
N +
/ M - 2
)
  A.  −
4 / 5
  B.  +
4 / 5
  C.  +
5 / 4
  D. −
5 / 4
     
   
View Answer 
  = 4÷(3+2)
  = 4÷5
  = 4× 1/5
  = 4/5
7.
9 / 20
−
[
1 / 5
+
{
1 / 4
+ 
(
5 / 6
−
/
1 / 3
+ 
1 / 2
)
}
]
= ?
  A.  
8 / 9
  B.  
1 / 4
  C.  
5 / 4
  D.  0
     
   
View Answer 
  = 9/20 − [1/5 + {1/4 + (5/6 - 5/6)}]
  = 9/20 − [1/5+{1/4+0}]
  = 9/20 − [1/5+1/4]
  = 9/20 − [9/20]
  = 9/20 − 9/20
  = 0
8.
1 / 4
+
[
1 / 4
−
{
1 / 4
+ 
(
1 / 4
− 
/
1 / 4
− 
1 / 4
)
}
]
= ?
  A.    0
  B.  −
1 / 2
  C.  − 1
  D.  +
3 / 4
     
   
View Answer 
  = 1/4+[1/4-{1/4+(1/4-0)}]
  = 1/4+[1/4-{1/4+1/4}]
  = 1/4+[1/4-{2/4}]
  = 1/4+[1/4-2/4]
  = 1/4-1/4
  = 0
9.
111
−
[
111 ÷
{
111 ×
(
111 ÷
/ 111 × 111
)
}
]
= ?
  A.  − 1
  B.  + 2
  C.    0
  D.  + 222
     
   
View Answer 
    = 111-[111 ÷ {111 ×(111 × 1/12321)}]
    = 111-[111 ÷ {111 ×(1/111)}]
    = 111-[111 ÷ {1}]
    = 111-111
    = 0
10.
2
+
[
2 + 2
{
2 −
(
2 −
/ 3 − 2
)
+3 −
(
/ 2 − 3
)
}
−  
{
3
(
2 −
/ 3 − 2
)
}
]
= 0
  A.  -8
  B.  11
  C.  3
  D.  8
     
   
View Answer 
  = 2+[2+2{2-(2-1)+3-(2-3)}-{3(2-1)}]
  = 2+[2+2{2-1+3-(-1)}-{3(1)}]
  = 2+[2+2{1+3+1}-{3}]
  = 2+[2+2{5}-3]
  = 2+[2+10-3]
  = 2+[9]
  = 2+9
  = 11
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