Shortcut:
logax =
logbx
/
logba
Here, log1227 = a
or,
log27
/
log12
= a
or, alog12 = log33
or, alog(3 x 4) = 3log3
or, a[log3 + log4] = 3log3
or, alog4 + alog3 = 3log3
or, alog22 = (3 − a)log3
or, 2alog2 = (3 − a)log3
or,
log2
/
log3
=
3 − a
/
2a
-----------(Eq i)
Now, log616 =
log16
/
log6
=
log24
/
log(2 x 3)
=
4log2
/
log2 + log3
=
4 x (log2/log3)
/
(log2/log3) + 1
=
4 x (3 − a/2a)
/
(3 − a/2a) + 1
=
4(3 − a)
/
3 + a
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