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View Answer
Short cut method:
ax/(a+b) + cy/c+d
/
x+y
x 100% gold
3x/4 + 5y/8
/
x+y
x 100% silver
Here,
a = 3
b = 1
c = 5
d = 3
x = 2
y = 1
Applying these values in short cut, we get:
=
6x + 5y
/
8(x+y)
x 100% -----------Eq (1)
Since, Ratio of silver to copper in the mixed alloy is 2:1
∴ Percentage quantity of silver in the mixed alloy = 2/3 x 100% = 200/3% -----------Eq (2)
From the Eq (1) & (2), we get
6x + 5y
/
8(x+y)
x 100% =
200
/
3
x 100%
6x + 5y
/
8(x+y)
x 100% =
2
/
3
18x + 15y = 16x + 16y
or 18x - 16x =16y-15y
2x = y
x/y = 1/2
&implies; x:y = 1:2
Hence the two alloys should be mixed in the ratio of 1:2
Suppose the two alloys are mixed in the ratio of x:y
Using the short cut method, percentage quantity of silver in the mixed alloy
=
3x/(a+b) + cy/c+d
/
x+y
x 100% gold
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